5(y+2)=2(3y+1)

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Solution for 5(y+2)=2(3y+1) equation: 



5(y+2)=2(3y+1)

We move all terms to the left:

5(y+2)-(2(3y+1))=0

We multiply parentheses

5y-(2(3y+1))+10=0



We calculate terms in parentheses: -(2(3y+1)), so:

2(3y+1)

We multiply parentheses

6y+2

Back to the equation:

-(6y+2)



We get rid of parentheses

5y-6y-2+10=0

We add all the numbers together, and all the variables

-1y+8=0

We move all terms containing y to the left, all other terms to the right

-y=-8

y=-8/-1

y=+8

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