5(y+2)=2y+28

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Solution for 5(y+2)=2y+28 equation:



5(y+2)=2y+28
We move all terms to the left:
5(y+2)-(2y+28)=0
We multiply parentheses
5y-(2y+28)+10=0
We get rid of parentheses
5y-2y-28+10=0
We add all the numbers together, and all the variables
3y-18=0
We move all terms containing y to the left, all other terms to the right
3y=18
y=18/3
y=6

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