5(y+2)=4(y+1)

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Solution for 5(y+2)=4(y+1) equation:


Simplifying
5(y + 2) = 4(y + 1)

Reorder the terms:
5(2 + y) = 4(y + 1)
(2 * 5 + y * 5) = 4(y + 1)
(10 + 5y) = 4(y + 1)

Reorder the terms:
10 + 5y = 4(1 + y)
10 + 5y = (1 * 4 + y * 4)
10 + 5y = (4 + 4y)

Solving
10 + 5y = 4 + 4y

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-4y' to each side of the equation.
10 + 5y + -4y = 4 + 4y + -4y

Combine like terms: 5y + -4y = 1y
10 + 1y = 4 + 4y + -4y

Combine like terms: 4y + -4y = 0
10 + 1y = 4 + 0
10 + 1y = 4

Add '-10' to each side of the equation.
10 + -10 + 1y = 4 + -10

Combine like terms: 10 + -10 = 0
0 + 1y = 4 + -10
1y = 4 + -10

Combine like terms: 4 + -10 = -6
1y = -6

Divide each side by '1'.
y = -6

Simplifying
y = -6

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