5(y+2)=4(y-1)

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Solution for 5(y+2)=4(y-1) equation: 



5(y+2)=4(y-1)

We move all terms to the left:

5(y+2)-(4(y-1))=0

We multiply parentheses

5y-(4(y-1))+10=0



We calculate terms in parentheses: -(4(y-1)), so:

4(y-1)

We multiply parentheses

4y-4

Back to the equation:

-(4y-4)



We get rid of parentheses

5y-4y+4+10=0

We add all the numbers together, and all the variables

y+14=0

We move all terms containing y to the left, all other terms to the right

y=-14

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