5(y+2)=6(y+1)

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Solution for 5(y+2)=6(y+1) equation: 



5(y+2)=6(y+1)

We move all terms to the left:

5(y+2)-(6(y+1))=0

We multiply parentheses

5y-(6(y+1))+10=0



We calculate terms in parentheses: -(6(y+1)), so:

6(y+1)

We multiply parentheses

6y+6

Back to the equation:

-(6y+6)



We get rid of parentheses

5y-6y-6+10=0

We add all the numbers together, and all the variables

-1y+4=0

We move all terms containing y to the left, all other terms to the right

-y=-4

y=-4/-1

y=+4

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