5(y+2)=8(y-1)

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Solution for 5(y+2)=8(y-1) equation: 



5(y+2)=8(y-1)

We move all terms to the left:

5(y+2)-(8(y-1))=0

We multiply parentheses

5y-(8(y-1))+10=0



We calculate terms in parentheses: -(8(y-1)), so:

8(y-1)

We multiply parentheses

8y-8

Back to the equation:

-(8y-8)



We get rid of parentheses

5y-8y+8+10=0

We add all the numbers together, and all the variables

-3y+18=0

We move all terms containing y to the left, all other terms to the right

-3y=-18

y=-18/-3

y=+6

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