5(y+3)+3(y+5)=7(y-5)-15

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Solution for 5(y+3)+3(y+5)=7(y-5)-15 equation: 



5(y+3)+3(y+5)=7(y-5)-15

We move all terms to the left:

5(y+3)+3(y+5)-(7(y-5)-15)=0

We multiply parentheses

5y+3y-(7(y-5)-15)+15+15=0



We calculate terms in parentheses: -(7(y-5)-15), so:

7(y-5)-15

We multiply parentheses

7y-35-15

We add all the numbers together, and all the variables

7y-50

Back to the equation:

-(7y-50)



We add all the numbers together, and all the variables

8y-(7y-50)+30=0

We get rid of parentheses

8y-7y+50+30=0

We add all the numbers together, and all the variables

y+80=0

We move all terms containing y to the left, all other terms to the right

y=-80

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