5(y+3)-4(2y-5)=-3y+3

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Solution for 5(y+3)-4(2y-5)=-3y+3 equation: 


Simplifying
5(y + 3) + -4(2y + -5) = -3y + 3

Reorder the terms:
5(3 + y) + -4(2y + -5) = -3y + 3
(3 * 5 + y * 5) + -4(2y + -5) = -3y + 3
(15 + 5y) + -4(2y + -5) = -3y + 3

Reorder the terms:
15 + 5y + -4(-5 + 2y) = -3y + 3
15 + 5y + (-5 * -4 + 2y * -4) = -3y + 3
15 + 5y + (20 + -8y) = -3y + 3

Reorder the terms:
15 + 20 + 5y + -8y = -3y + 3

Combine like terms: 15 + 20 = 35
35 + 5y + -8y = -3y + 3

Combine like terms: 5y + -8y = -3y
35 + -3y = -3y + 3

Reorder the terms:
35 + -3y = 3 + -3y

Add '3y' to each side of the equation.
35 + -3y + 3y = 3 + -3y + 3y

Combine like terms: -3y + 3y = 0
35 + 0 = 3 + -3y + 3y
35 = 3 + -3y + 3y

Combine like terms: -3y + 3y = 0
35 = 3 + 0
35 = 3

Solving
35 = 3

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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