5(y+3)-7=10-2y

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Solution for 5(y+3)-7=10-2y equation: 



5(y+3)-7=10-2y

We move all terms to the left:

5(y+3)-7-(10-2y)=0

We add all the numbers together, and all the variables

5(y+3)-(-2y+10)-7=0

We multiply parentheses

5y-(-2y+10)+15-7=0

We get rid of parentheses

5y+2y-10+15-7=0

We add all the numbers together, and all the variables

7y-2=0

We move all terms containing y to the left, all other terms to the right

7y=2

y=2/7

y=2/7

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