5(y+3)=2y+36

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Solution for 5(y+3)=2y+36 equation: 



5(y+3)=2y+36

We move all terms to the left:

5(y+3)-(2y+36)=0

We multiply parentheses

5y-(2y+36)+15=0

We get rid of parentheses

5y-2y-36+15=0

We add all the numbers together, and all the variables

3y-21=0

We move all terms containing y to the left, all other terms to the right

3y=21

y=21/3

y=7

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