5(y+3)=2y=20

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Solution for 5(y+3)=2y=20 equation: 



5(y+3)=2y=20

We move all terms to the left:

5(y+3)-(2y)=0

We add all the numbers together, and all the variables

-2y+5(y+3)=0

We multiply parentheses

-2y+5y+15=0

We add all the numbers together, and all the variables

3y+15=0

We move all terms containing y to the left, all other terms to the right

3y=-15

y=-15/3

y=-5

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