5(y+3)=3(y+3)+6

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Solution for 5(y+3)=3(y+3)+6 equation: 



5(y+3)=3(y+3)+6

We move all terms to the left:

5(y+3)-(3(y+3)+6)=0

We multiply parentheses

5y-(3(y+3)+6)+15=0



We calculate terms in parentheses: -(3(y+3)+6), so:

3(y+3)+6

We multiply parentheses

3y+9+6

We add all the numbers together, and all the variables

3y+15

Back to the equation:

-(3y+15)



We get rid of parentheses

5y-3y-15+15=0

We add all the numbers together, and all the variables

2y=0

y=0/2

y=0

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