5(y+3)=39+2y

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Solution for 5(y+3)=39+2y equation: 



5(y+3)=39+2y

We move all terms to the left:

5(y+3)-(39+2y)=0

We add all the numbers together, and all the variables

5(y+3)-(2y+39)=0

We multiply parentheses

5y-(2y+39)+15=0

We get rid of parentheses

5y-2y-39+15=0

We add all the numbers together, and all the variables

3y-24=0

We move all terms containing y to the left, all other terms to the right

3y=24

y=24/3

y=8

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