5(y+3)=4y+15

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Solution for 5(y+3)=4y+15 equation: 



5(y+3)=4y+15

We move all terms to the left:

5(y+3)-(4y+15)=0

We multiply parentheses

5y-(4y+15)+15=0

We get rid of parentheses

5y-4y-15+15=0

We add all the numbers together, and all the variables

y=0

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