5(y+3)=4y+15

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Solution for 5(y+3)=4y+15 equation:



5(y+3)=4y+15
We move all terms to the left:
5(y+3)-(4y+15)=0
We multiply parentheses
5y-(4y+15)+15=0
We get rid of parentheses
5y-4y-15+15=0
We add all the numbers together, and all the variables
y=0

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