5(y+4)+10(y-3)+2=

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Solution for 5(y+4)+10(y-3)+2= equation:


Simplifying
5(y + 4) + 10(y + -3) + 2 = 0

Reorder the terms:
5(4 + y) + 10(y + -3) + 2 = 0
(4 * 5 + y * 5) + 10(y + -3) + 2 = 0
(20 + 5y) + 10(y + -3) + 2 = 0

Reorder the terms:
20 + 5y + 10(-3 + y) + 2 = 0
20 + 5y + (-3 * 10 + y * 10) + 2 = 0
20 + 5y + (-30 + 10y) + 2 = 0

Reorder the terms:
20 + -30 + 2 + 5y + 10y = 0

Combine like terms: 20 + -30 = -10
-10 + 2 + 5y + 10y = 0

Combine like terms: -10 + 2 = -8
-8 + 5y + 10y = 0

Combine like terms: 5y + 10y = 15y
-8 + 15y = 0

Solving
-8 + 15y = 0

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '8' to each side of the equation.
-8 + 8 + 15y = 0 + 8

Combine like terms: -8 + 8 = 0
0 + 15y = 0 + 8
15y = 0 + 8

Combine like terms: 0 + 8 = 8
15y = 8

Divide each side by '15'.
y = 0.5333333333

Simplifying
y = 0.5333333333

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