5(y+4)=2(3y+7)-5

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Solution for 5(y+4)=2(3y+7)-5 equation: 



5(y+4)=2(3y+7)-5

We move all terms to the left:

5(y+4)-(2(3y+7)-5)=0

We multiply parentheses

5y-(2(3y+7)-5)+20=0



We calculate terms in parentheses: -(2(3y+7)-5), so:

2(3y+7)-5

We multiply parentheses

6y+14-5

We add all the numbers together, and all the variables

6y+9

Back to the equation:

-(6y+9)



We get rid of parentheses

5y-6y-9+20=0

We add all the numbers together, and all the variables

-1y+11=0

We move all terms containing y to the left, all other terms to the right

-y=-11

y=-11/-1

y=+11

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