5(y+5)+4(5y+20)=4(y+5)+4(4y+5)

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Solution for 5(y+5)+4(5y+20)=4(y+5)+4(4y+5) equation: 



5(y+5)+4(5y+20)=4(y+5)+4(4y+5)

We move all terms to the left:

5(y+5)+4(5y+20)-(4(y+5)+4(4y+5))=0

We multiply parentheses

5y+20y-(4(y+5)+4(4y+5))+25+80=0



We calculate terms in parentheses: -(4(y+5)+4(4y+5)), so:

4(y+5)+4(4y+5)

We multiply parentheses

4y+16y+20+20

We add all the numbers together, and all the variables

20y+40

Back to the equation:

-(20y+40)



We add all the numbers together, and all the variables

25y-(20y+40)+105=0

We get rid of parentheses

25y-20y-40+105=0

We add all the numbers together, and all the variables

5y+65=0

We move all terms containing y to the left, all other terms to the right

5y=-65

y=-65/5

y=-13

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