5(y+5)+4(5y+20)=4(y+5)+4(4y+5)

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Solution for 5(y+5)+4(5y+20)=4(y+5)+4(4y+5) equation:



5(y+5)+4(5y+20)=4(y+5)+4(4y+5)
We move all terms to the left:
5(y+5)+4(5y+20)-(4(y+5)+4(4y+5))=0
We multiply parentheses
5y+20y-(4(y+5)+4(4y+5))+25+80=0
We calculate terms in parentheses: -(4(y+5)+4(4y+5)), so:
4(y+5)+4(4y+5)
We multiply parentheses
4y+16y+20+20
We add all the numbers together, and all the variables
20y+40
Back to the equation:
-(20y+40)
We add all the numbers together, and all the variables
25y-(20y+40)+105=0
We get rid of parentheses
25y-20y-40+105=0
We add all the numbers together, and all the variables
5y+65=0
We move all terms containing y to the left, all other terms to the right
5y=-65
y=-65/5
y=-13

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