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5(y+5)y=3
We move all terms to the left:
5(y+5)y-(3)=0
We multiply parentheses
5y^2+25y-3=0
a = 5; b = 25; c = -3;
Δ = b2-4ac
Δ = 252-4·5·(-3)
Δ = 685
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(25)-\sqrt{685}}{2*5}=\frac{-25-\sqrt{685}}{10} $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(25)+\sqrt{685}}{2*5}=\frac{-25+\sqrt{685}}{10} $
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