5(y+7)+y=4(y+4)+4

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Solution for 5(y+7)+y=4(y+4)+4 equation:



5(y+7)+y=4(y+4)+4
We move all terms to the left:
5(y+7)+y-(4(y+4)+4)=0
We add all the numbers together, and all the variables
y+5(y+7)-(4(y+4)+4)=0
We multiply parentheses
y+5y-(4(y+4)+4)+35=0
We calculate terms in parentheses: -(4(y+4)+4), so:
4(y+4)+4
We multiply parentheses
4y+16+4
We add all the numbers together, and all the variables
4y+20
Back to the equation:
-(4y+20)
We add all the numbers together, and all the variables
6y-(4y+20)+35=0
We get rid of parentheses
6y-4y-20+35=0
We add all the numbers together, and all the variables
2y+15=0
We move all terms containing y to the left, all other terms to the right
2y=-15
y=-15/2
y=-7+1/2

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