5(y+7)+y=4(y+4)+4

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Solution for 5(y+7)+y=4(y+4)+4 equation: 



5(y+7)+y=4(y+4)+4

We move all terms to the left:

5(y+7)+y-(4(y+4)+4)=0

We add all the numbers together, and all the variables

y+5(y+7)-(4(y+4)+4)=0

We multiply parentheses

y+5y-(4(y+4)+4)+35=0



We calculate terms in parentheses: -(4(y+4)+4), so:

4(y+4)+4

We multiply parentheses

4y+16+4

We add all the numbers together, and all the variables

4y+20

Back to the equation:

-(4y+20)



We add all the numbers together, and all the variables

6y-(4y+20)+35=0

We get rid of parentheses

6y-4y-20+35=0

We add all the numbers together, and all the variables

2y+15=0

We move all terms containing y to the left, all other terms to the right

2y=-15

y=-15/2

y=-7+1/2

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