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5(y+8)-1/2(1-y)=1
We move all terms to the left:
5(y+8)-1/2(1-y)-(1)=0
Domain of the equation: 2(1-y)!=0We add all the numbers together, and all the variables
y∈R
5(y+8)-1/2(-1y+1)-1=0
We multiply parentheses
5y-1/2(-1y+1)+40-1=0
We multiply all the terms by the denominator
5y*2(-1y+1)+40*2(-1y+1)-1*2(-1y+1)-1=0
Wy multiply elements
10y^2(-+80y(--2y(--1=0
We use the square of the difference formula
10y^2(-80y(+2y(+1=0
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