5(y-1)+16(2y+3)=3(2y-7)

Solution for 5(y-1)+16(2y+3)=3(2y-7) equation:

5(y-1)+16(2y+3)=3(2y-7)

We move all terms to the left:

5(y-1)+16(2y+3)-(3(2y-7))=0

We multiply parentheses

5y+32y-(3(2y-7))-5+48=0


We calculate terms in parentheses: -(3(2y-7)), so:

3(2y-7)

We multiply parentheses

6y-21

Back to the equation:

-(6y-21)


We add all the numbers together, and all the variables

37y-(6y-21)+43=0

We get rid of parentheses

37y-6y+21+43=0

We add all the numbers together, and all the variables

31y+64=0

We move all terms containing y to the left, all other terms to the right

31y=-64

y=-64/31

y=-2+2/31