5(y-1)-3(y-2)+2(y+3)=0

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Solution for 5(y-1)-3(y-2)+2(y+3)=0 equation: 



5(y-1)-3(y-2)+2(y+3)=0

We multiply parentheses

5y-3y+2y-5+6+6=0

We add all the numbers together, and all the variables

4y+7=0

We move all terms containing y to the left, all other terms to the right

4y=-7

y=-7/4

y=-1+3/4

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