5(y-1)=2y+4-3(-7y-2)

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Solution for 5(y-1)=2y+4-3(-7y-2) equation: 



5(y-1)=2y+4-3(-7y-2)

We move all terms to the left:

5(y-1)-(2y+4-3(-7y-2))=0

We multiply parentheses

5y-(2y+4-3(-7y-2))-5=0



We calculate terms in parentheses: -(2y+4-3(-7y-2)), so:

2y+4-3(-7y-2)

determiningTheFunctionDomain
2y-3(-7y-2)+4

We multiply parentheses

2y+21y+6+4

We add all the numbers together, and all the variables

23y+10

Back to the equation:

-(23y+10)



We get rid of parentheses

5y-23y-10-5=0

We add all the numbers together, and all the variables

-18y-15=0

We move all terms containing y to the left, all other terms to the right

-18y=15

y=15/-18

y=-5/6

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