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5(y-1)=3(2y-5)-(1-3y
We move all terms to the left:
5(y-1)-(3(2y-5)-(1-3y)=0
We add all the numbers together, and all the variables
5(y-1)-(3(2y-5)-(-3y+1)=0
We multiply parentheses
5y-(3(2y-5)-(-3y+1)-5=0
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