5(y-1)=3(2y-5-(1-3y)

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Solution for 5(y-1)=3(2y-5-(1-3y) equation: 



5(y-1)=3(2y-5-(1-3y)

We move all terms to the left:

5(y-1)-(3(2y-5-(1-3y))=0

We add all the numbers together, and all the variables

5(y-1)-(3(2y-5-(-3y+1))=0

We multiply parentheses

5y-(3(2y-5-(-3y+1))-5=0

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