5(y-1)=4y+5-3(-5y-2)

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Solution for 5(y-1)=4y+5-3(-5y-2) equation: 



5(y-1)=4y+5-3(-5y-2)

We move all terms to the left:

5(y-1)-(4y+5-3(-5y-2))=0

We multiply parentheses

5y-(4y+5-3(-5y-2))-5=0



We calculate terms in parentheses: -(4y+5-3(-5y-2)), so:

4y+5-3(-5y-2)

determiningTheFunctionDomain
4y-3(-5y-2)+5

We multiply parentheses

4y+15y+6+5

We add all the numbers together, and all the variables

19y+11

Back to the equation:

-(19y+11)



We get rid of parentheses

5y-19y-11-5=0

We add all the numbers together, and all the variables

-14y-16=0

We move all terms containing y to the left, all other terms to the right

-14y=16

y=16/-14

y=-1+1/7

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