5(y-1)=5y+2-3(-2y-1)

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Solution for 5(y-1)=5y+2-3(-2y-1) equation: 



5(y-1)=5y+2-3(-2y-1)

We move all terms to the left:

5(y-1)-(5y+2-3(-2y-1))=0

We multiply parentheses

5y-(5y+2-3(-2y-1))-5=0



We calculate terms in parentheses: -(5y+2-3(-2y-1)), so:

5y+2-3(-2y-1)

determiningTheFunctionDomain
5y-3(-2y-1)+2

We multiply parentheses

5y+6y+3+2

We add all the numbers together, and all the variables

11y+5

Back to the equation:

-(11y+5)



We get rid of parentheses

5y-11y-5-5=0

We add all the numbers together, and all the variables

-6y-10=0

We move all terms containing y to the left, all other terms to the right

-6y=10

y=10/-6

y=-1+2/3

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