5(y-1)=y+1-6(-3y-2)

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Solution for 5(y-1)=y+1-6(-3y-2) equation: 



5(y-1)=y+1-6(-3y-2)

We move all terms to the left:

5(y-1)-(y+1-6(-3y-2))=0

We multiply parentheses

5y-(y+1-6(-3y-2))-5=0



We calculate terms in parentheses: -(y+1-6(-3y-2)), so:

y+1-6(-3y-2)

determiningTheFunctionDomain
y-6(-3y-2)+1

We multiply parentheses

y+18y+12+1

We add all the numbers together, and all the variables

19y+13

Back to the equation:

-(19y+13)



We get rid of parentheses

5y-19y-13-5=0

We add all the numbers together, and all the variables

-14y-18=0

We move all terms containing y to the left, all other terms to the right

-14y=18

y=18/-14

y=-1+2/7

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