5(y-2)+1=9y-8

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Solution for 5(y-2)+1=9y-8 equation: 



5(y-2)+1=9y-8

We move all terms to the left:

5(y-2)+1-(9y-8)=0

We multiply parentheses

5y-(9y-8)-10+1=0

We get rid of parentheses

5y-9y+8-10+1=0

We add all the numbers together, and all the variables

-4y-1=0

We move all terms containing y to the left, all other terms to the right

-4y=1

y=1/-4

y=-1/4

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