5(y-2)-2(4y+3)=5

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Solution for 5(y-2)-2(4y+3)=5 equation: 



5(y-2)-2(4y+3)=5

We move all terms to the left:

5(y-2)-2(4y+3)-(5)=0

We multiply parentheses

5y-8y-10-6-5=0

We add all the numbers together, and all the variables

-3y-21=0

We move all terms containing y to the left, all other terms to the right

-3y=21

y=21/-3

y=-7

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