5(y-2)-2=2(v+1)-5

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Solution for 5(y-2)-2=2(v+1)-5 equation: 


Simplifying
5(y + -2) + -2 = 2(v + 1) + -5

Reorder the terms:
5(-2 + y) + -2 = 2(v + 1) + -5
(-2 * 5 + y * 5) + -2 = 2(v + 1) + -5
(-10 + 5y) + -2 = 2(v + 1) + -5

Reorder the terms:
-10 + -2 + 5y = 2(v + 1) + -5

Combine like terms: -10 + -2 = -12
-12 + 5y = 2(v + 1) + -5

Reorder the terms:
-12 + 5y = 2(1 + v) + -5
-12 + 5y = (1 * 2 + v * 2) + -5
-12 + 5y = (2 + 2v) + -5

Reorder the terms:
-12 + 5y = 2 + -5 + 2v

Combine like terms: 2 + -5 = -3
-12 + 5y = -3 + 2v

Solving
-12 + 5y = -3 + 2v

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '12' to each side of the equation.
-12 + 12 + 5y = -3 + 12 + 2v

Combine like terms: -12 + 12 = 0
0 + 5y = -3 + 12 + 2v
5y = -3 + 12 + 2v

Combine like terms: -3 + 12 = 9
5y = 9 + 2v

Divide each side by '5'.
y = 1.8 + 0.4v

Simplifying
y = 1.8 + 0.4v

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