5(y-2)-2=2(y+2)-5

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Solution for 5(y-2)-2=2(y+2)-5 equation: 



5(y-2)-2=2(y+2)-5

We move all terms to the left:

5(y-2)-2-(2(y+2)-5)=0

We multiply parentheses

5y-(2(y+2)-5)-10-2=0



We calculate terms in parentheses: -(2(y+2)-5), so:

2(y+2)-5

We multiply parentheses

2y+4-5

We add all the numbers together, and all the variables

2y-1

Back to the equation:

-(2y-1)



We add all the numbers together, and all the variables

5y-(2y-1)-12=0

We get rid of parentheses

5y-2y+1-12=0

We add all the numbers together, and all the variables

3y-11=0

We move all terms containing y to the left, all other terms to the right

3y=11

y=11/3

y=3+2/3

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