5(y-2)-3=-3(-6y+9)-9y

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Solution for 5(y-2)-3=-3(-6y+9)-9y equation: 



5(y-2)-3=-3(-6y+9)-9y

We move all terms to the left:

5(y-2)-3-(-3(-6y+9)-9y)=0

We multiply parentheses

5y-(-3(-6y+9)-9y)-10-3=0



We calculate terms in parentheses: -(-3(-6y+9)-9y), so:

-3(-6y+9)-9y

We add all the numbers together, and all the variables

-9y-3(-6y+9)

We multiply parentheses

-9y+18y-27

We add all the numbers together, and all the variables

9y-27

Back to the equation:

-(9y-27)



We add all the numbers together, and all the variables

5y-(9y-27)-13=0

We get rid of parentheses

5y-9y+27-13=0

We add all the numbers together, and all the variables

-4y+14=0

We move all terms containing y to the left, all other terms to the right

-4y=-14

y=-14/-4

y=3+1/2

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