5(y-2)-7=-3(-4y+5)-3y

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Solution for 5(y-2)-7=-3(-4y+5)-3y equation: 



5(y-2)-7=-3(-4y+5)-3y

We move all terms to the left:

5(y-2)-7-(-3(-4y+5)-3y)=0

We multiply parentheses

5y-(-3(-4y+5)-3y)-10-7=0



We calculate terms in parentheses: -(-3(-4y+5)-3y), so:

-3(-4y+5)-3y

We add all the numbers together, and all the variables

-3y-3(-4y+5)

We multiply parentheses

-3y+12y-15

We add all the numbers together, and all the variables

9y-15

Back to the equation:

-(9y-15)



We add all the numbers together, and all the variables

5y-(9y-15)-17=0

We get rid of parentheses

5y-9y+15-17=0

We add all the numbers together, and all the variables

-4y-2=0

We move all terms containing y to the left, all other terms to the right

-4y=2

y=2/-4

y=-1/2

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