5(y-2)-7=-5(-3y+1)-2y

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Solution for 5(y-2)-7=-5(-3y+1)-2y equation: 



5(y-2)-7=-5(-3y+1)-2y

We move all terms to the left:

5(y-2)-7-(-5(-3y+1)-2y)=0

We multiply parentheses

5y-(-5(-3y+1)-2y)-10-7=0



We calculate terms in parentheses: -(-5(-3y+1)-2y), so:

-5(-3y+1)-2y

We add all the numbers together, and all the variables

-2y-5(-3y+1)

We multiply parentheses

-2y+15y-5

We add all the numbers together, and all the variables

13y-5

Back to the equation:

-(13y-5)



We add all the numbers together, and all the variables

5y-(13y-5)-17=0

We get rid of parentheses

5y-13y+5-17=0

We add all the numbers together, and all the variables

-8y-12=0

We move all terms containing y to the left, all other terms to the right

-8y=12

y=12/-8

y=-1+1/2

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