5(y-2)=2(y+3)-16

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Solution for 5(y-2)=2(y+3)-16 equation: 



5(y-2)=2(y+3)-16

We move all terms to the left:

5(y-2)-(2(y+3)-16)=0

We multiply parentheses

5y-(2(y+3)-16)-10=0



We calculate terms in parentheses: -(2(y+3)-16), so:

2(y+3)-16

We multiply parentheses

2y+6-16

We add all the numbers together, and all the variables

2y-10

Back to the equation:

-(2y-10)



We get rid of parentheses

5y-2y+10-10=0

We add all the numbers together, and all the variables

3y=0

y=0/3

y=0

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