5(y-2)=2(y-9)+3y

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Solution for 5(y-2)=2(y-9)+3y equation:


Simplifying
5(y + -2) = 2(y + -9) + 3y

Reorder the terms:
5(-2 + y) = 2(y + -9) + 3y
(-2 * 5 + y * 5) = 2(y + -9) + 3y
(-10 + 5y) = 2(y + -9) + 3y

Reorder the terms:
-10 + 5y = 2(-9 + y) + 3y
-10 + 5y = (-9 * 2 + y * 2) + 3y
-10 + 5y = (-18 + 2y) + 3y

Combine like terms: 2y + 3y = 5y
-10 + 5y = -18 + 5y

Add '-5y' to each side of the equation.
-10 + 5y + -5y = -18 + 5y + -5y

Combine like terms: 5y + -5y = 0
-10 + 0 = -18 + 5y + -5y
-10 = -18 + 5y + -5y

Combine like terms: 5y + -5y = 0
-10 = -18 + 0
-10 = -18

Solving
-10 = -18

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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