5(y-2)=2y+2+3(y-4)

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Solution for 5(y-2)=2y+2+3(y-4) equation: 


Simplifying
5(y + -2) = 2y + 2 + 3(y + -4)

Reorder the terms:
5(-2 + y) = 2y + 2 + 3(y + -4)
(-2 * 5 + y * 5) = 2y + 2 + 3(y + -4)
(-10 + 5y) = 2y + 2 + 3(y + -4)

Reorder the terms:
-10 + 5y = 2y + 2 + 3(-4 + y)
-10 + 5y = 2y + 2 + (-4 * 3 + y * 3)
-10 + 5y = 2y + 2 + (-12 + 3y)

Reorder the terms:
-10 + 5y = 2 + -12 + 2y + 3y

Combine like terms: 2 + -12 = -10
-10 + 5y = -10 + 2y + 3y

Combine like terms: 2y + 3y = 5y
-10 + 5y = -10 + 5y

Add '10' to each side of the equation.
-10 + 10 + 5y = -10 + 10 + 5y

Combine like terms: -10 + 10 = 0
0 + 5y = -10 + 10 + 5y
5y = -10 + 10 + 5y

Combine like terms: -10 + 10 = 0
5y = 0 + 5y
5y = 5y

Add '-5y' to each side of the equation.
5y + -5y = 5y + -5y

Combine like terms: 5y + -5y = 0
0 = 5y + -5y

Combine like terms: 5y + -5y = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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