5(y-3)+2y=20

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Solution for 5(y-3)+2y=20 equation: 



5(y-3)+2y=20

We move all terms to the left:

5(y-3)+2y-(20)=0

We add all the numbers together, and all the variables

2y+5(y-3)-20=0

We multiply parentheses

2y+5y-15-20=0

We add all the numbers together, and all the variables

7y-35=0

We move all terms containing y to the left, all other terms to the right

7y=35

y=35/7

y=5

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