5(y-3)+4y=21

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Solution for 5(y-3)+4y=21 equation: 



5(y-3)+4y=21

We move all terms to the left:

5(y-3)+4y-(21)=0

We add all the numbers together, and all the variables

4y+5(y-3)-21=0

We multiply parentheses

4y+5y-15-21=0

We add all the numbers together, and all the variables

9y-36=0

We move all terms containing y to the left, all other terms to the right

9y=36

y=36/9

y=4

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