5(y-3)-1=-7(-3y+1)-y

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Solution for 5(y-3)-1=-7(-3y+1)-y equation: 



5(y-3)-1=-7(-3y+1)-y

We move all terms to the left:

5(y-3)-1-(-7(-3y+1)-y)=0

We multiply parentheses

5y-(-7(-3y+1)-y)-15-1=0



We calculate terms in parentheses: -(-7(-3y+1)-y), so:

-7(-3y+1)-y

We add all the numbers together, and all the variables

-1y-7(-3y+1)

We multiply parentheses

-1y+21y-7

We add all the numbers together, and all the variables

20y-7

Back to the equation:

-(20y-7)



We add all the numbers together, and all the variables

5y-(20y-7)-16=0

We get rid of parentheses

5y-20y+7-16=0

We add all the numbers together, and all the variables

-15y-9=0

We move all terms containing y to the left, all other terms to the right

-15y=9

y=9/-15

y=-3/5

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