5(y-3)-4(3y+4)=20

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Solution for 5(y-3)-4(3y+4)=20 equation: 



5(y-3)-4(3y+4)=20

We move all terms to the left:

5(y-3)-4(3y+4)-(20)=0

We multiply parentheses

5y-12y-15-16-20=0

We add all the numbers together, and all the variables

-7y-51=0

We move all terms containing y to the left, all other terms to the right

-7y=51

y=51/-7

y=-7+2/7

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