5(y-3)-4(y+2)=2+3(1-2y)

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Solution for 5(y-3)-4(y+2)=2+3(1-2y) equation: 



5(y-3)-4(y+2)=2+3(1-2y)

We move all terms to the left:

5(y-3)-4(y+2)-(2+3(1-2y))=0

We add all the numbers together, and all the variables

5(y-3)-4(y+2)-(2+3(-2y+1))=0

We multiply parentheses

5y-4y-(2+3(-2y+1))-15-8=0



We calculate terms in parentheses: -(2+3(-2y+1)), so:

2+3(-2y+1)

determiningTheFunctionDomain
3(-2y+1)+2

We multiply parentheses

-6y+3+2

We add all the numbers together, and all the variables

-6y+5

Back to the equation:

-(-6y+5)



We add all the numbers together, and all the variables

y-(-6y+5)-23=0

We get rid of parentheses

y+6y-5-23=0

We add all the numbers together, and all the variables

7y-28=0

We move all terms containing y to the left, all other terms to the right

7y=28

y=28/7

y=4

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