5(y-3)-8=-2(-9y+4)-7y

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Solution for 5(y-3)-8=-2(-9y+4)-7y equation: 



5(y-3)-8=-2(-9y+4)-7y

We move all terms to the left:

5(y-3)-8-(-2(-9y+4)-7y)=0

We multiply parentheses

5y-(-2(-9y+4)-7y)-15-8=0



We calculate terms in parentheses: -(-2(-9y+4)-7y), so:

-2(-9y+4)-7y

We add all the numbers together, and all the variables

-7y-2(-9y+4)

We multiply parentheses

-7y+18y-8

We add all the numbers together, and all the variables

11y-8

Back to the equation:

-(11y-8)



We add all the numbers together, and all the variables

5y-(11y-8)-23=0

We get rid of parentheses

5y-11y+8-23=0

We add all the numbers together, and all the variables

-6y-15=0

We move all terms containing y to the left, all other terms to the right

-6y=15

y=15/-6

y=-2+1/2

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