5(y-3)-9=-3(-7y+4)-y

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Solution for 5(y-3)-9=-3(-7y+4)-y equation: 



5(y-3)-9=-3(-7y+4)-y

We move all terms to the left:

5(y-3)-9-(-3(-7y+4)-y)=0

We multiply parentheses

5y-(-3(-7y+4)-y)-15-9=0



We calculate terms in parentheses: -(-3(-7y+4)-y), so:

-3(-7y+4)-y

We add all the numbers together, and all the variables

-1y-3(-7y+4)

We multiply parentheses

-1y+21y-12

We add all the numbers together, and all the variables

20y-12

Back to the equation:

-(20y-12)



We add all the numbers together, and all the variables

5y-(20y-12)-24=0

We get rid of parentheses

5y-20y+12-24=0

We add all the numbers together, and all the variables

-15y-12=0

We move all terms containing y to the left, all other terms to the right

-15y=12

y=12/-15

y=-4/5

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