5(y-3)-9=-3(-8y+2)-5y

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Solution for 5(y-3)-9=-3(-8y+2)-5y equation:



5(y-3)-9=-3(-8y+2)-5y
We move all terms to the left:
5(y-3)-9-(-3(-8y+2)-5y)=0
We multiply parentheses
5y-(-3(-8y+2)-5y)-15-9=0
We calculate terms in parentheses: -(-3(-8y+2)-5y), so:
-3(-8y+2)-5y
We add all the numbers together, and all the variables
-5y-3(-8y+2)
We multiply parentheses
-5y+24y-6
We add all the numbers together, and all the variables
19y-6
Back to the equation:
-(19y-6)
We add all the numbers together, and all the variables
5y-(19y-6)-24=0
We get rid of parentheses
5y-19y+6-24=0
We add all the numbers together, and all the variables
-14y-18=0
We move all terms containing y to the left, all other terms to the right
-14y=18
y=18/-14
y=-1+2/7

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