5(y-3)-9=-3(-8y+2)-5y

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Solution for 5(y-3)-9=-3(-8y+2)-5y equation: 



5(y-3)-9=-3(-8y+2)-5y

We move all terms to the left:

5(y-3)-9-(-3(-8y+2)-5y)=0

We multiply parentheses

5y-(-3(-8y+2)-5y)-15-9=0



We calculate terms in parentheses: -(-3(-8y+2)-5y), so:

-3(-8y+2)-5y

We add all the numbers together, and all the variables

-5y-3(-8y+2)

We multiply parentheses

-5y+24y-6

We add all the numbers together, and all the variables

19y-6

Back to the equation:

-(19y-6)



We add all the numbers together, and all the variables

5y-(19y-6)-24=0

We get rid of parentheses

5y-19y+6-24=0

We add all the numbers together, and all the variables

-14y-18=0

We move all terms containing y to the left, all other terms to the right

-14y=18

y=18/-14

y=-1+2/7

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