5(y-3)-y=2(2y+4)

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Solution for 5(y-3)-y=2(2y+4) equation: 



5(y-3)-y=2(2y+4)

We move all terms to the left:

5(y-3)-y-(2(2y+4))=0

We add all the numbers together, and all the variables

-1y+5(y-3)-(2(2y+4))=0

We multiply parentheses

-1y+5y-(2(2y+4))-15=0



We calculate terms in parentheses: -(2(2y+4)), so:

2(2y+4)

We multiply parentheses

4y+8

Back to the equation:

-(4y+8)



We add all the numbers together, and all the variables

4y-(4y+8)-15=0

We get rid of parentheses

4y-4y-8-15=0

We add all the numbers together, and all the variables

-23!=0

There is no solution for this equation

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