5(y-3)=-2(4y-4)+3

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Solution for 5(y-3)=-2(4y-4)+3 equation: 



5(y-3)=-2(4y-4)+3

We move all terms to the left:

5(y-3)-(-2(4y-4)+3)=0

We multiply parentheses

5y-(-2(4y-4)+3)-15=0



We calculate terms in parentheses: -(-2(4y-4)+3), so:

-2(4y-4)+3

We multiply parentheses

-8y+8+3

We add all the numbers together, and all the variables

-8y+11

Back to the equation:

-(-8y+11)



We get rid of parentheses

5y+8y-11-15=0

We add all the numbers together, and all the variables

13y-26=0

We move all terms containing y to the left, all other terms to the right

13y=26

y=26/13

y=2

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