5(y-3)=-2(4y-4)+3

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Solution for 5(y-3)=-2(4y-4)+3 equation:



5(y-3)=-2(4y-4)+3
We move all terms to the left:
5(y-3)-(-2(4y-4)+3)=0
We multiply parentheses
5y-(-2(4y-4)+3)-15=0
We calculate terms in parentheses: -(-2(4y-4)+3), so:
-2(4y-4)+3
We multiply parentheses
-8y+8+3
We add all the numbers together, and all the variables
-8y+11
Back to the equation:
-(-8y+11)
We get rid of parentheses
5y+8y-11-15=0
We add all the numbers together, and all the variables
13y-26=0
We move all terms containing y to the left, all other terms to the right
13y=26
y=26/13
y=2

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