5(y-3)=3(2y-5)

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Solution for 5(y-3)=3(2y-5) equation: 



5(y-3)=3(2y-5)

We move all terms to the left:

5(y-3)-(3(2y-5))=0

We multiply parentheses

5y-(3(2y-5))-15=0



We calculate terms in parentheses: -(3(2y-5)), so:

3(2y-5)

We multiply parentheses

6y-15

Back to the equation:

-(6y-15)



We get rid of parentheses

5y-6y+15-15=0

We add all the numbers together, and all the variables

-y=0

y=0/-1

y=0

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