5(y-4)+2y=5(y-2)

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Solution for 5(y-4)+2y=5(y-2) equation: 



5(y-4)+2y=5(y-2)

We move all terms to the left:

5(y-4)+2y-(5(y-2))=0

We add all the numbers together, and all the variables

2y+5(y-4)-(5(y-2))=0

We multiply parentheses

2y+5y-(5(y-2))-20=0



We calculate terms in parentheses: -(5(y-2)), so:

5(y-2)

We multiply parentheses

5y-10

Back to the equation:

-(5y-10)



We add all the numbers together, and all the variables

7y-(5y-10)-20=0

We get rid of parentheses

7y-5y+10-20=0

We add all the numbers together, and all the variables

2y-10=0

We move all terms containing y to the left, all other terms to the right

2y=10

y=10/2

y=5

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